-13y^2+36=-y

Solution for -13y^2+36=-y equation:

-13y^2+36=-y

We move all terms to the left:

-13y^2+36-(-y)=0

We add all the numbers together, and all the variables

-13y^2-(-1y)+36=0

We get rid of parentheses

-13y^2+1y+36=0

We add all the numbers together, and all the variables

-13y^2+y+36=0

a = -13; b = 1; c = +36;
Δ = b2-4ac
Δ = 12-4·(-13)·36
Δ = 1873
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1873}}{2*-13}=\frac{-1-\sqrt{1873}}{-26}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1873}}{2*-13}=\frac{-1+\sqrt{1873}}{-26}
$